if i was not wrong, evo fuel pump quite weak
normality78 said:yup. im running emanage now. its a piggyback.
on off boost, its all minus until the end liao but still damn rich. but whn run in boost, its enaugh as its still got more. its still in minus side though... i was being told that if s/alone thn no such problem coz s/alone injector driver is more capable
cipan_supercas said:Use the injector size compensation utility found inside the E-Manage Tuning Software. What's wrong with your tuner? He don't understand how to use the software ? Or are you trying to monkey with somwthing you don't understand?
edgar_raphael said:Hi normality, I have the formula for calculating the size of injectors best suit you. I've done this based on research from various sources. Hope this helps.
Get the size of the injector in flow (cc/m) then divide that by 10.4, which gives you the imperial rating of the injector in lbs/hr. The overall horsepower potential of that injector is now gained by a simple multiplication by two. Then subtract 10 per cent to give a ‘real world’ margin and you have the true horsepower number that a single injector will flow. Multiply this by the number of injectors and you have the results. Take for example:
550cc divided by 10.4 = 53 (rounded)
53 lb/hr multiplied by two = 106
106hp with 10 percent subtracted = 96 (rounded)
96 multiplied by four = 384
384hp should be roughly these injectors’ total flow
You need to use some nous when performing these mental gymnastics, though, as taking the results literally can be confusing. For example you would expect that possibly, at a push 400hp should be within the range of the 550cc injectors. From there its easy to do these mental calculations whenever the subject arises, and even though it’s far from the most scientific approach, the results are very accurate. All you need to do now that the sizing issue is under control is to start saving.
Working the other way round, say your aim is to hit a mild 300hp, work the calculations from bottom up:
300hp divided by 4 = 75hp
75hp with 10 percent addition = 82.5hp
82.5hp divided by 2 = 41.25 lb/hr
41.25 lb/hr multiply by 10.4 = 429 cc
Formula : ( cc) flow of injectors / 10.4 = [ lb/hr ]
( lb/hr ) X 2 = [ hp ] horsepower potential of injectors
( hp ) - 10% = [ hp ] in ‘real world margin’
( hp ) X no. of injectors = HP of injectors total flow
normality78 said:cipan_supercas,
what does injector size compensation utility work as?