hmm..
lets see if my formula is rite..
21W
W=V*I , 21=12*I
I=W/V , 1.75 = 21/12, each bulb consume about 1.75A
3W
I=3/12 , 0.25=3/12, each 3W led only consume 0.25A
so, 1.75 - 0.25 = 1.5A, need to dissipate about 1.5A at each bulb thats has been replaced by LED.
V=I*R
R=V/I , 8=12/1.5, each LED needs 8ohm resistor parallel to it.
eh, is this rite? 8ohms at each LED bulb?:hmmmm:

btw, resistor use should be at least 3W ceramic type .
btw, im not sure this is rite or wrong. 8ohms seems to low value.
need others to give opinion/ideas.
other alternative u can modify the stock (or spare) flasher relay.
try using different capacitor value inside the relay. im not sure either higher or lower value. forgot already.